1 00:00:00,690 --> 00:00:04,429 In this video, I'm going to revise what we have done today in class. 2 00:00:04,990 --> 00:00:09,330 I'm going to teach you how to find the equation for a certain law, 3 00:00:10,109 --> 00:00:16,190 starting with a table of data, like the ones that you have found for the period and the length. 4 00:00:16,649 --> 00:00:20,010 Thanks to Javier Pinel, who provided with this data, that are very good. 5 00:00:20,609 --> 00:00:22,149 And this is where we need to start. 6 00:00:22,890 --> 00:00:26,109 I also will need a calculator, here I have one, 7 00:00:26,109 --> 00:00:32,229 and a ruler to make the graph as good or as nice as possible so I'm going to 8 00:00:32,229 --> 00:00:40,740 start by making the graph okay so I'm going to put like the ruler here this is 9 00:00:40,740 --> 00:00:51,060 going to be sorry about that okay this is going to be the x-axis I use the 10 00:00:51,060 --> 00:00:57,899 ruler now I'm going to use it again to write or to create to draw the vertical 11 00:00:57,899 --> 00:01:11,849 axis okay so these are the vertical and the horizontal axis that we need or 12 00:01:11,849 --> 00:01:16,709 we also need always need in the graph next I'm going to write the length in 13 00:01:16,709 --> 00:01:22,650 the horizontal axis and I need to remember this of the length is going to 14 00:01:22,650 --> 00:01:30,299 be here okay and the period that is symbolized by a capital T is going to be 15 00:01:30,299 --> 00:01:36,659 on the vertical axis this is the period is measured in seconds I need to choose 16 00:01:36,659 --> 00:01:40,359 the scales I'm going to start here for example is going to be I'm not don't 17 00:01:40,359 --> 00:01:46,379 need to start with zeros I'm going to start with 0.7 meters here this is going 18 00:01:46,379 --> 00:02:00,519 to be 0.8 0.9 and finally one meter okay this is this is the information that is 19 00:02:00,519 --> 00:02:04,900 provided here in the first column of the table. Then in the vertical axis I'm 20 00:02:04,900 --> 00:02:08,800 going to represent the period. Starting, for example, I'm going to start here like 21 00:02:08,800 --> 00:02:16,300 this is 1.9. Notice that it's not necessary that I start in the 0, 0. I can 22 00:02:16,300 --> 00:02:22,120 start or my origin can be other point. The important thing is to use as much of 23 00:02:22,120 --> 00:02:30,159 the space as I can. Then this is 1 and let's say this is going to be 2, 2, 1, yes. 24 00:02:30,159 --> 00:03:04,900 and do like this is 2.0 2.1 2.2 2.3 and sorry this is for 2.2 again 2.2 is 2.3 25 00:03:04,900 --> 00:03:13,020 and it's a little bit and this is 2.4 I'm going to take this out I want to 26 00:03:13,020 --> 00:03:20,300 make it nice okay so this is going to be two point four seconds seconds and I 27 00:03:20,300 --> 00:03:26,099 remember the period is here and now I need to plot the points of the table so 28 00:03:26,099 --> 00:03:33,000 zero point seven corresponds to a period of one point and almost two so she's 29 00:03:33,000 --> 00:03:38,400 zero point seven is here almost two it must be around here okay this is my 30 00:03:38,400 --> 00:03:45,800 first point of the graph, my first plot of the graph. Next is 0.8, 8 is 2.1 and a 31 00:03:45,800 --> 00:03:55,500 quarter. So this is 0.8, 2.1 and a quarter must be around here. So this is my 32 00:03:55,500 --> 00:04:12,909 second point 0.9 match with 2.25 2.25 2.2 25 is exactly this line between 2.2 and 33 00:04:12,909 --> 00:04:25,089 2.3 and finally 1.0 matches 2.372 that is more or less here between 2.5 and 34 00:04:25,089 --> 00:04:36,120 and 2.4 as you can see the points are almost in a straight line particularly 35 00:04:36,120 --> 00:04:42,839 this they are in a straight line okay we can see this okay it's a very good set 36 00:04:42,839 --> 00:04:56,660 of data so we can even write this draw a straight line but I want to make it nice 37 00:04:56,660 --> 00:05:09,350 and I don't know how it doesn't work okay so we have kind of a straight line 38 00:05:09,350 --> 00:05:14,269 and now as it is a straight line we can say that the period and the length is 39 00:05:14,269 --> 00:05:20,329 proportional so we can say that our law has going to be a formula like this the 40 00:05:20,329 --> 00:05:28,610 period is proportional to the length and what you need to do is to find which 41 00:05:28,610 --> 00:05:36,589 number is this constant this K is called the slope the bigger the slope the more 42 00:05:36,589 --> 00:05:44,110 inclined is the is a straight line to find the decay to find the constant we 43 00:05:44,110 --> 00:05:48,949 have to work out this kind of equation if we I'm going to take this out I don't 44 00:05:48,949 --> 00:05:56,689 need it anymore so to find K if you work out this 45 00:05:56,689 --> 00:06:07,610 equation you will see that the constant K is the period divided by the length so 46 00:06:07,610 --> 00:06:11,730 we are going to go to this table and in this table using the same I'm going to 47 00:06:11,730 --> 00:06:15,949 write the constant for each pair of values I'm going to start for example 48 00:06:15,949 --> 00:06:23,689 with 0.7 and 1.985 so I go to my calculator and the constant is 1 point 49 00:06:23,689 --> 00:06:36,790 sorry I had to change the version the constant is one one point nine eight 50 00:06:36,790 --> 00:06:45,910 five divided by zero point seven so this is my first value of the constant I'm 51 00:06:45,910 --> 00:06:50,149 going to write I have four the same three decimals here four figures I have 52 00:06:50,149 --> 00:06:57,529 one here. I'm going to set it in the middle. I'm going to use three. 53 00:06:57,529 --> 00:07:09,019 For this set of values 2.84. The constant has units as the 54 00:07:09,019 --> 00:07:14,779 period is seconds and the length is meters. This is seconds times meters. So we can 55 00:07:14,779 --> 00:07:20,600 write the units of the constant as seconds times meters. We can do the same 56 00:07:20,600 --> 00:07:50,740 with the next pair of values, I mean, 2.125 divided by 0.8 and you can see that the constant 57 00:07:50,740 --> 00:08:01,720 is not exactly the same but it's quite similar so 2.65 and the units are the 58 00:08:01,720 --> 00:08:12,240 same okay let's find the third value for the constant we divide zero sorry two 59 00:08:12,240 --> 00:08:25,589 point two point two five zero we divide this by zero point nine this number 60 00:08:25,589 --> 00:08:33,750 divided by this number okay and again the constant is not exactly the same but 61 00:08:33,750 --> 00:08:46,259 it's quite similar 2.50 and seconds per meter and to put this properly and I 62 00:08:46,259 --> 00:08:52,059 only have now one set one pair of values a length of one meter and this is very 63 00:08:52,059 --> 00:09:01,740 easy so the constant is 2.37 seconds per meter so these are the four values of the constant 64 00:09:02,379 --> 00:09:07,580 what is the real value for the constant we are going to do the average the average constant 65 00:09:14,220 --> 00:09:26,929 i'm going to do in a different color the average constant in spanish la media we calculate by 66 00:09:26,929 --> 00:09:50,169 By adding these four numbers, 2.84 plus 2.65 plus 2.50 and 2.37, 67 00:09:52,169 --> 00:09:58,450 another these numbers, divided by 4, because I have four total numbers. 68 00:09:58,450 --> 00:10:20,210 Ok, so we need to use our calculator now to do this, so is 2.84 plus 2.65 plus 2.50 plus 69 00:10:20,210 --> 00:10:47,789 two sorry plus two point thirty point thirty seven and we divide this number 70 00:10:47,789 --> 00:11:00,559 by four ten point this calculator works in a funny way so two point five nine two 71 00:11:00,559 --> 00:11:08,539 comma five nine is the average value of the constant. We will accept that as the 72 00:11:08,539 --> 00:11:17,379 real value. Don't forget the units. The units, remember, were seconds over meter. 73 00:11:17,379 --> 00:11:23,419 Okay? So now we can write the final equation for our experiment. The period 74 00:11:23,419 --> 00:11:35,460 is proportional to the length and the proportional constant the K is 2.54 okay 75 00:11:35,460 --> 00:11:45,429 this would be like our final result for our experiment I hope it helps remember 76 00:11:45,429 --> 00:11:50,710 you have to do the activity about the number of batteries and the intensity of 77 00:11:50,710 --> 00:11:57,590 of the electric current in a circuit okay class see you next day