1 00:00:00,000 --> 00:00:05,820 Worked example of a parallel circuit. This is a parallel circuit in which you have to 2 00:00:05,820 --> 00:00:10,960 calculate the following questions. The total equivalent resistance of the circuit. 3 00:00:11,539 --> 00:00:17,000 The total current flowing through the circuit. The current flowing through each resistor. 4 00:00:18,140 --> 00:00:21,140 The voltage or potential difference across each resistor. 5 00:00:21,820 --> 00:00:26,019 The power supplied by the cell and the power dissipated in the circuit. 6 00:00:26,019 --> 00:00:32,240 The data you are given is the value of the resistors in parallel and the voltage of the cell. 7 00:00:33,579 --> 00:00:36,600 Firstly, the total equivalent resistance of the circuit. 8 00:00:37,640 --> 00:00:43,640 It is really important you calculate it correctly, because you will use this value in the rest of the exercise. 9 00:00:44,859 --> 00:00:50,520 I in this case, you have three resistors in parallel of 30, 90, and 180 ohms. 10 00:00:50,520 --> 00:00:56,600 we obtain the total resistance of the circuit by grouping all the resistors in parallel together 11 00:00:56,600 --> 00:01:03,840 remember to use calculator and that the result 0 0 5 it is the inverse of the equivalent resistase 12 00:01:03,840 --> 00:01:09,900 we're looking for to calculate the total equivalent current we need to apply ohm's law to the 13 00:01:09,900 --> 00:01:15,379 equivalent circuit intensity is equal to the voltage of the cell divided by the equivalent 14 00:01:15,379 --> 00:01:22,099 resistance. The current flowing through each resistor. This is a parallel circuit so all of 15 00:01:22,099 --> 00:01:28,079 the resistors have a voltage of 3V which is the cell voltage. We calculate each intensity with 16 00:01:28,079 --> 00:01:33,620 the Ohm's law. We confirm that the total current is the sum of the three currents flowing through 17 00:01:33,620 --> 00:01:39,200 each branch. As we said before the voltage or potential difference across all resistors is 18 00:01:39,200 --> 00:01:45,280 the same and equal to 3V because resistors are in parallel. The dissipated power is the sum of 19 00:01:45,280 --> 00:01:50,840 the power consumed by each resistor. You can calculate each power with the product of voltage 20 00:01:50,840 --> 00:01:56,799 and intensity. We confirm that the delivered power and the power dissipated in the circuit are equal.