1 00:00:00,180 --> 00:00:17,579 This is block 5. Three resistors in parallel of 3, 9 and 18 ohms on a cell of 3 volts. First, you have to calculate the equivalent resistance. Remember the equation, the formula that you have to use. 2 00:00:17,579 --> 00:00:27,420 The inverse of the equivalent resistance is there equal to the addition of the three inverses of the addition of the three of them. 3 00:00:28,019 --> 00:00:35,420 So take the calculator and make this operation 1 divided by 3 plus 1 divided by 9 plus 1 divided by 18. 4 00:00:35,799 --> 00:00:37,420 And the result is 0.5. 5 00:00:37,500 --> 00:00:38,640 This is not the result. 6 00:00:38,759 --> 00:00:39,439 This is nothing. 7 00:00:40,259 --> 00:00:45,020 The equivalent resistance is the inverse of this result. 8 00:00:45,020 --> 00:01:05,459 So take your calculator and divide. 1 divided by 0.5. The result is 2. So you can check that the equivalent resistance of three resistors in parallel, the total equivalent resistance is lower than the lowest of them. 9 00:01:05,459 --> 00:01:10,700 So, 2, that's it, is lower than 3. It's okay. 10 00:01:11,739 --> 00:01:15,439 Intensity of the circuit is always voltage of the cell divided by the equivalent resistance, 11 00:01:15,620 --> 00:01:18,599 so 3 divided by 2, 1.5 amperes. 12 00:01:20,180 --> 00:01:24,620 They are asking you to calculate intensity in the three of the resistors, 13 00:01:24,739 --> 00:01:27,000 but first you need to know what is the voltage. 14 00:01:27,680 --> 00:01:30,219 The voltage in a circuit in parallel is always the same 15 00:01:30,219 --> 00:01:33,120 because the three resistors are connected to the same terminals. 16 00:01:33,120 --> 00:01:41,780 and these are the terminals of the cell so voltage in the three of the resistors is always the same 17 00:01:41,780 --> 00:01:47,480 the voltage of the cell three volts because it's in parallel then now you can calculate the 18 00:01:47,480 --> 00:01:54,040 intensity in the three of the of the resistors remember that the intensity of the c-kit is 19 00:01:54,040 --> 00:02:00,140 divided in each of the branches of the c-kit so it's going to be divided in three into three 20 00:02:00,140 --> 00:02:15,860 In which amount? Well, we apply the Ohm's law. Remember that the Ohm's law, voltage, intensity, resistance, the intensity, it's voltage divided by resistance. 21 00:02:16,860 --> 00:02:19,000 So, let's apply this formula. 22 00:02:20,740 --> 00:02:30,699 Intensity in the resistor number 1, that is, well, sorry, this is one of 3 Ohms, is 3 volts divided by 3 Ohms. 3 divided by 3, 1 ampere. 23 00:02:30,699 --> 00:02:37,740 the intensity in the number two of nine ohms is three volts divided by nine ohms so the result is 24 00:02:37,740 --> 00:02:45,819 0.33 amperes you can reduce only to two figures decimal figures and intensity in three voltage 25 00:02:45,819 --> 00:02:53,659 of three is in the resistance three remember it's always the same three volts divided by 18 ohms 26 00:02:53,659 --> 00:03:04,919 and the result is 0.16 amperes and this is uh you have a infinite figure so you can put 0.17 27 00:03:04,919 --> 00:03:09,740 it's always safe and the last question you have to calculate the power generated and the power 28 00:03:09,740 --> 00:03:15,379 dissipated in each of the resistors so the body where regenerated is the voltage of the cell 29 00:03:15,379 --> 00:03:29,060 by the total intensity 3 volts by 1.5 amperes you have 4.5 5 watts this is the power regenerated by 30 00:03:29,060 --> 00:03:39,139 the cell and in each of the resistors to dissipate a certain amount of of power you have to calculate 31 00:03:39,139 --> 00:03:45,020 with the this product voltage by intensity in each of the resistors check 32 00:03:45,020 --> 00:03:52,280 that the addition of the power dissipated 3 plus 1 plus 0.5 it's equal 33 00:03:52,280 --> 00:03:57,719 to the power generated and one other thing that I forgot is to say that the 34 00:03:57,719 --> 00:04:04,379 intensity in the in a resistor in a signaling part in parallel these 35 00:04:04,379 --> 00:04:09,939 intensities are directly inversely proportional to the resistors so the 36 00:04:09,939 --> 00:04:17,759 bigger is the resistance the smaller is the intensity you can check this out