1 00:00:00,000 --> 00:00:05,599 Parallel Cirque. In these circuits, the load devices are connected on different branches 2 00:00:05,599 --> 00:00:10,500 of the wire. There are several possible paths for the electric current to flow through. 3 00:00:11,240 --> 00:00:15,900 The electric current is split across all the possible paths and more current will circulate 4 00:00:15,900 --> 00:00:20,760 through the branch that offers the least resistance. The current intensity that flows 5 00:00:20,760 --> 00:00:25,980 through each load device is different. Even if one of the load devices stops working, 6 00:00:25,980 --> 00:00:29,660 the rest continue to work because the electric current takes another path, 7 00:00:30,000 --> 00:00:35,759 the circuit is closed by another path. The energy supplied by the cell reaches each branch of the 8 00:00:35,759 --> 00:00:41,500 circuit directly. Therefore, all the lamps shine with the same brightness as a single lamp located 9 00:00:41,500 --> 00:00:48,700 on a single branch. However, the cell will run down sooner. To simplify things, we will solve 10 00:00:48,700 --> 00:00:54,640 a circuit formed by three resistors connected in parallel to a cell. The equivalent resistance of 11 00:00:54,640 --> 00:01:00,380 a circuit with parallel resistors is calculated using this formula. Since this circuit is 12 00:01:00,380 --> 00:01:04,900 equivalent to the last one, the current flowing through the two circuits will be the same. 13 00:01:05,819 --> 00:01:10,120 We apply Ohm's law to calculate the current flowing through the equivalent resistance. 14 00:01:11,079 --> 00:01:17,140 Since the resistors are in parallel, the potential drop or voltage is the same in them all and it is 15 00:01:17,140 --> 00:01:25,780 equal to the cell voltage. Vt equals V1 equals V2 equals V3. By contrast, the total intensity 16 00:01:25,780 --> 00:01:31,939 through the circuit is divided across all the resistors. We can calculate this with Ohm's law. 17 00:01:32,900 --> 00:01:38,019 The total intensity is divided through the resistors in parallel, so the addition of the 18 00:01:38,019 --> 00:01:44,159 intensities should give the total intensity. The inverse of the equivalent resistance is equal to 19 00:01:44,159 --> 00:01:50,319 the sum of the inverses of all resistances in the circuit. The current of the equivalent circuit is 20 00:01:50,319 --> 00:01:56,140 equal to the sum of the currents flowing across each of the resistors. The total voltage delivered 21 00:01:56,140 --> 00:02:02,959 by the power source is the same as the potential drops across each of the resistors. Example of a 22 00:02:02,959 --> 00:02:09,139 parallel circuit. From the parallel circuit shown in the figure, calculate the current flowing 23 00:02:09,139 --> 00:02:15,780 through each resistor and the potential drop across each one. First, we use the above formula 24 00:02:15,780 --> 00:02:23,319 to calculate the equivalent resistance. You need to use the calculator. Remember that the formula 25 00:02:23,319 --> 00:02:28,520 gives you the inverse of the equivalent resistance, so you need to calculate the inverse. 26 00:02:29,759 --> 00:02:35,360 Again use the calculator. We use Ohm's law to calculate the total current. 27 00:02:35,360 --> 00:02:40,960 The potential drop in each branch is equal to the voltage supplied by the cell. 28 00:02:42,060 --> 00:02:44,759 To calculate the current flowing through each resistor, 29 00:02:45,300 --> 00:02:49,319 we apply Ohm's law using the voltage values that we just calculated. 30 00:02:50,419 --> 00:02:54,719 So divide the cell voltage between each of the values of the resistors. 31 00:02:55,280 --> 00:03:00,520 We can check that we have done the exercise correctly by adding up the current of all the 32 00:03:00,520 --> 00:03:04,759 resistors. The result should be equal to the total current. 33 00:03:05,360 --> 00:03:05,979 you