1 00:00:00,000 --> 00:00:06,160 In a series parallel circuit, you have to use the specific characteristics of series or parallel 2 00:00:06,160 --> 00:00:12,679 in each branch of the circuit. In the circuit, you can see here there is a resistor in series 3 00:00:12,679 --> 00:00:18,440 with two that are in parallel. Firstly, calculate the equivalent resistance. 4 00:00:19,460 --> 00:00:24,679 You calculate the resistors that are in parallel and then add the one that is in series. 5 00:00:24,679 --> 00:00:30,780 The second question is the total current, remember is always the voltage of the cell 6 00:00:30,780 --> 00:00:37,000 divided by the equivalent resistance. In this exercise they are asking for the currents trough 7 00:00:37,000 --> 00:00:43,560 each resistor, the resistor 1 is in series with the cell, so the intensity is the same that in 8 00:00:43,560 --> 00:00:51,340 the circuit. But this intensity is divide between the two resistors in parallel. The voltage here 9 00:00:51,340 --> 00:00:57,740 is not the voltage of the cell. You can calculate it because the voltage is the difference between 10 00:00:57,740 --> 00:01:03,979 the voltage of the cell and the voltage of the resistor 1. Other way to calculate the intensities 11 00:01:03,979 --> 00:01:10,519 is through the divisor of intensities. It is a proportion between the equivalent resistance in 12 00:01:10,519 --> 00:01:17,700 the parallel branch and the resistance of each of the parallel resistors. You decide with way is easier.