0 00:00:00,000 --> 00:00:01,000 Lock 4. 1 00:00:01,000 --> 00:00:03,000 Types of circuits. 2 00:00:03,000 --> 00:00:05,000 Series and parallel. 3 00:00:06,000 --> 00:00:07,000 Electricity. 4 00:00:07,000 --> 00:00:09,000 Series circuits. 5 00:00:09,000 --> 00:00:13,000 In these circuits, all the components are connected one after the other. 6 00:00:14,000 --> 00:00:18,000 This way, all the current flows through all the load devices. 7 00:00:18,000 --> 00:00:22,000 There is only one possible path for the electric current to flow through. 8 00:00:23,000 --> 00:00:26,000 The same current flows through all the load devices. 9 00:00:27,000 --> 00:00:32,000 If one load device stops working, none of them will work because the circuit will be open. 10 00:00:33,000 --> 00:00:38,000 This happens when one of the load devices fails or is not connected to the circuit properly. 11 00:00:38,000 --> 00:00:43,000 The energy supplied by the cell must be divided across all the load devices. 12 00:00:44,000 --> 00:00:48,000 In the circuit in the drawing on the left, the energy is divided among the three lamps, 13 00:00:48,000 --> 00:00:53,000 which all light up to the same level but do not shine as brightly as a single lamp would. 14 00:00:54,000 --> 00:00:55,000 Parallel circuits. 15 00:00:56,000 --> 00:01:00,000 In these circuits, the load devices are connected on different branches of the wire. 16 00:01:01,000 --> 00:01:05,000 There are several possible paths for the electric current to flow through. 17 00:01:06,000 --> 00:01:09,000 The electric current is split across all the possible paths 18 00:01:09,000 --> 00:01:13,000 and more current will circulate through the branch that offers the least resistance. 19 00:01:14,000 --> 00:01:17,000 The current intensity that flows through each load device is different. 20 00:01:18,000 --> 00:01:21,000 Even if one of the load devices stops working, 21 00:01:21,000 --> 00:01:25,000 the rest continue to work because the electric current takes another path, 22 00:01:25,000 --> 00:01:27,000 the circuit is closed by another path. 23 00:01:28,000 --> 00:01:32,000 The energy supplied by the cell reaches each branch of the circuit directly. 24 00:01:33,000 --> 00:01:38,000 Therefore, all the lamps shine with the same brightness as a single lamp located on a single branch. 25 00:01:39,000 --> 00:01:42,000 However, the cell will run down sooner. 26 00:01:43,000 --> 00:01:45,000 Series-parallel combination circuits. 27 00:01:46,000 --> 00:01:50,000 These circuits contain devices connected in series and in parallel. 28 00:01:51,000 --> 00:01:56,000 In this case, the circuits have properties of both series circuits and parallel circuits. 29 00:01:57,000 --> 00:01:58,000 Solving circuits. 30 00:01:59,000 --> 00:02:04,000 To learn how to solve circuits, we generally begin with circuits composed only of cells and resistors. 31 00:02:05,000 --> 00:02:10,000 The way that we put these resistors together is called the association of resistors. 32 00:02:11,000 --> 00:02:14,000 This gives us the three types of basic circuits that we have just seen. 33 00:02:15,000 --> 00:02:21,000 To calculate an unknown variable in a series, parallel or series-parallel combination circuit, 34 00:02:21,000 --> 00:02:27,000 we add all the resistors together and replace them with a single one, which we call the total resistance. 35 00:02:28,000 --> 00:02:32,000 This way, we make the circuit equivalent to a simple circuit with just one resistor. 36 00:02:33,000 --> 00:02:38,000 With this simple circuit, we can apply Ohm's law to make our calculations quickly 37 00:02:38,000 --> 00:02:40,000 and then calculate the values for each resistor. 38 00:02:41,000 --> 00:02:45,000 The circuit formed with the equivalent resistors is called an equivalent circuit. 39 00:02:46,000 --> 00:02:49,000 We can obtain two things from this circuit. 40 00:02:50,000 --> 00:02:52,000 The currents flowing through the circuit. 41 00:02:53,000 --> 00:02:56,000 The potential drops taking place across the components. 42 00:02:57,000 --> 00:02:58,000 Solving series circuits. 43 00:02:59,000 --> 00:03:06,000 To simplify things, we will solve a circuit formed by three resistors connected in series to a cell. 44 00:03:06,000 --> 00:03:12,000 We will solve it in the same way that we would solve any circuit with resistors connected in series, 45 00:03:12,000 --> 00:03:14,000 regardless of how many there are. 46 00:03:15,000 --> 00:03:19,000 We calculate the equivalent resistance of a series circuit 47 00:03:19,000 --> 00:03:22,000 by adding up the values of all the resistors in the circuit. 48 00:03:23,000 --> 00:03:24,000 In this case, 49 00:03:25,000 --> 00:03:28,000 Rt equals R1 plus R2 plus R3. 50 00:03:29,000 --> 00:03:35,000 And the equivalent circuit is one with only one resistor with the equivalent resistance. 51 00:03:36,000 --> 00:03:39,000 Since this circuit is equivalent to the last one, 52 00:03:39,000 --> 00:03:42,000 the current flowing through the two circuits will be the same. 53 00:03:43,000 --> 00:03:48,000 We apply Ohm's law to calculate the current flowing through the equivalent resistance. 54 00:03:49,000 --> 00:03:51,000 Since the resistors are in series, 55 00:03:51,000 --> 00:03:56,000 the current is the same in them all and it is equal to the total current of the circuit. 56 00:03:57,000 --> 00:04:03,000 By contrast, the total voltage or potential difference supplied by the cell or power source 57 00:04:03,000 --> 00:04:05,000 is divided across all the resistors. 58 00:04:06,000 --> 00:04:08,000 We can calculate this with Ohm's law. 59 00:04:09,000 --> 00:04:13,000 It must hold that all the energy supplied by the cell, Vt, 60 00:04:13,000 --> 00:04:17,000 will be equal to the potential drop across each resistor. 61 00:04:17,000 --> 00:04:22,000 Relationship between the variables of the real circuit and the equivalent circuit. 62 00:04:23,000 --> 00:04:28,000 The equivalent resistance is equal to the sum of all resistances in the circuit. 63 00:04:29,000 --> 00:04:32,000 The current flowing through all of the resistors in the circuit is the same 64 00:04:32,000 --> 00:04:35,000 and is equal to the current of the equivalent circuit. 65 00:04:36,000 --> 00:04:39,000 The total voltage delivered by the power source 66 00:04:39,000 --> 00:04:42,000 is the sum of the potential drops across each of the resistors. 67 00:04:43,000 --> 00:04:45,000 Worked example of a series circuit. 68 00:04:46,000 --> 00:04:48,000 From the series circuit shown in the figure, 69 00:04:49,000 --> 00:04:54,000 calculate the current flowing through each resistor and the potential drop across each one. 70 00:04:54,000 --> 00:04:59,000 First, we calculate the equivalent resistance by adding up all the resistances. 71 00:05:00,000 --> 00:05:03,000 The equivalent resistance is 500 Ohms. 72 00:05:04,000 --> 00:05:07,000 This figure shows the resulting equivalent circuit. 73 00:05:08,000 --> 00:05:11,000 We use Ohm's law to calculate the total current. 74 00:05:11,000 --> 00:05:13,000 This gives us 20 mA. 75 00:05:14,000 --> 00:05:16,000 Since this is a series circuit, 76 00:05:16,000 --> 00:05:21,000 the total current of the circuit is the same current that flows across each of the resistors in the circuit. 77 00:05:22,000 --> 00:05:25,000 To calculate the potential drops across each resistor, 78 00:05:25,000 --> 00:05:29,000 we apply Ohm's law in each resistor using the current values that we just calculated. 79 00:05:30,000 --> 00:05:35,000 We can check that we have done the exercise correctly by adding up the potential drops. 80 00:05:35,000 --> 00:05:40,000 The result should be equal to the total voltage supplied by the cell that is 10 volts. 81 00:05:41,000 --> 00:05:46,000 VT equals V1 plus V2 equals 4V plus 6V equals 10V.