3ºTEDI EXERCISES BLOCK 4 RESISTORS IN SERIES

This is the block 4, the C-Kitsin series. 00:00:00

In this exercise you have to calculate several questions here. 00:00:05

First, I recommend you to draw the C-Kit. 00:00:11

Three resistors in series and the cell. 00:00:17

First questions. 00:00:20

The first question is to calculate the equivalent resistance. 00:00:22

The equivalent resistance in C-kitting series is the addition of all the resistors that you have in the C-kit. 00:00:26

So, you have this result. 00:00:35

The total current always is the voltage of the cell divided by the equivalent resistance. 00:00:37

Make the calculation with the calculator. 00:00:43

In the following question, they are asking you the current in every of the resistors. 00:00:47

here what you have to know is a property of the circuits in series the intensity or current is 00:00:53

always the same so it's equal to the total intensity because there is only one path for 00:01:03

the electron for the electrons to go through the circuit but in question d they are asking you to 00:01:09

calculate the voltage in every of the resistors then apply the ohm's law in each of the resistors 00:01:18

because you know the intensity and you know the resistance and then calculate in each resistor 00:01:24

that's why i call them voltage sub one means for the voltage in the resistor number one 00:01:33

intensity by resistance in all of them use the calculator again so you always 00:01:41

have the same intensity and this is the resistance of this of each of them check 00:01:47

that the addition of the three voltages is the voltage of the cell you can use a 00:01:54

calculator to check this in the last question they are asking you to 00:02:01

calculate the power, the power generated by the cell and the power dissipated by each 00:02:08

of the resistors. The power is the voltage by the intensity. So the power generated is 00:02:13

the voltage of the cell by the total intensity of the circuit. Then the power generated is 00:02:20

this amount. The power dissipated is dissipated in each of the resistors that they are the 00:02:27

load devices the devices that are creating our work in each oven you can 00:02:33

calculate the voltage by the intensity because you know it from the previous 00:02:39

questions so to calculate the power in the first resistance the power in the 00:02:45

second and the power in the third and multiplying the voltages that you 00:02:50

obtain and the intensity remember that was the same the unit of the power is 00:02:55

the bat and it's really little the these figures are really little because the voltage of the cell 00:03:01

was only three volts is really small and the intensity was only 0.1 amperes one thing that 00:03:09

you have to check is that the addition of the three power dissipated in each of the resistors 00:03:18

the addition of these three is exactly the same as the power that you have in the cell. 00:03:27

That's why we can say that the power generated is equal to the power dissipated in the circuit. 00:03:33

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