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tpr2_u4: circuit_ohmslaw1 - Contenido educativo
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How to measure the voltage drop across a lamp in a series circuit
Hello, I'm going to do one of the compulsory activities we have in this lesson, in this unit, unit 4
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ICT activities, electric circuits, here we have two different parts, circuit diagrams and the Ohm's law
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I'm going to do one of them
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The AMS law refers to the way of connecting a voltmeter in parallel with a resistor and an ammeter here
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We need to open the circuit to connect the ammeter
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The circuit is this one, the series circuit, paper activity 18
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First I'm going to do it without looking at this activity
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To connect the voltmeter, we need to use this simulator
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So I click here
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And now what I have to do is to draw this circuit
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The series circuit made up of a battery and three different lamps
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Here in the circuit we are going to use this lamp and all the lamps are the same lamp
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It doesn't matter in order to know how to connect the voltmeter
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So we have this lamp, another lamp, this other lamp
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And I need to use wires to complete the circuit
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This wire and two more, one and two
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So when I switch off, switch on the switch
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I see that the lamps are lighting up
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Ok, now
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what the instructions say is
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after drawing the circuit, we need to
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use the voltmeter to measure voltage drop across L2
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L2, so the voltage drop
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between B and C
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the second lamp, this lamp
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here we have the multimeter, the voltmeter
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and meter and everything
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so, voltmeter is here, I click here
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to measure voltage, and for that
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we need to close the circuit, now current is
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flowing through the circuit
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But if we want to change the voltage, here we have a 6 volt battery, so we can change this value, 6 volts
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And now what I have to do is to connect in parallel the voltmeter with this lamp, lamp number 2, this way
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Ok, first, I'm going to see if the voltmeter is working
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The battery is a 6-volt battery, so I can check this. I connect the probe, this one and two probes, here, and I see that it's working.
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So the voltage drop across these two points in the circuit is 6 volts. But what I have to measure is the voltage drop across this lamp. So here and there, 2 volts.
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It's clear because, as I said, the lamps are equal, so each of them has a voltage drop of 2 volts.
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2 plus 2 plus 2, 6 volts in total.
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Okay, thank you.
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- Subido por:
- Maximino R.
- Licencia:
- Reconocimiento - No comercial - Compartir igual
- Visualizaciones:
- 133
- Fecha:
- 27 de marzo de 2020 - 21:11
- Visibilidad:
- Público
- Centro:
- IES ALFREDO KRAUS
- Duración:
- 04′ 15″
- Relación de aspecto:
- 1.78:1
- Resolución:
- 1920x1080 píxeles
- Tamaño:
- 7.95 MBytes