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Circuitos con condensadores - Contenido educativo

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Subido el 26 de julio de 2023 por Ivan P.

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hello again I'm going to explain the last thing of the of the of the unit 00:00:00
yeah that is how to calculate total capacity of a circuit okay it's it's not 00:00:07
difficult this this part okay so let's go directly to an example so for instance 00:00:22
we have this case we have two capacitors yeah in this way this way think thinking 00:00:36
resistances and when we studied this before we said that this is a parallel 00:00:53
or serious serious circuit yes it's a parallel circuit yeah yeah so in using 00:01:03
resistances a do you remember the formula yeah 00:01:19
over r1 plus 1 over r2 plus blah blah blah yeah nothing else yeah but using 00:01:33
capacitors this goes in a different way but not in a in a in a difficult way 00:01:45
because it's it works in the opposite way so we see a parallel circuit think 00:01:53
in serious circuit using resistances so for instance if you have here 1 milli 00:02:03
farad and here 2 milli farad the total capacity of the circuit is total capacity 00:02:10
is let me call this c1 and this c2 yeah so the total capacity would be 1 milli 00:02:26
farad plus 2 milli farads 3 milli farads and that's all okay and if we have more 00:02:39
than two condensers capacitors connected like this okay like this we just need to 00:02:55
add them okay the total capacity would be the summatory of each one okay do you understand 00:03:16
this summatory if you don't understand forget this and think just in um and adding one by 00:03:28
one okay okay so new one new one no I don't want yeah so it's a parallel what happens if we have 00:03:38
this example one and another capacitor imagine two milli farads and four milli farad are they 00:03:49
in parallel or is a serious secret yes serious secret okay serious secret so think in the opposite 00:04:08
way when it's not like resistances now the total value is using the formula yeah but but we are 00:04:22
going to use the we are going to be cheaters yeah so we are going to we are going to use the trick 00:04:37
the trick remember total capacity is the division of what here we multiply the values and here we 00:04:45
add the values it only function with two two capacitors if we have three we would need to add 00:04:56
this and this and then this this and this now we need to do this formula the formula with two and 00:05:07
then the result with the other one okay okay so we have two if we have the same units we can forget 00:05:19
the units for a while and we type the units at the end to multiply by four here two four okay so this 00:05:29
is 8 over 6 we can do this for this its value is 1.33333 as I said to decimals milli farads 00:05:43
okay because we have milli farads here in both capacitors okay I'm not going to to put more than 00:06:07
that so maybe three but not more than three imagine that here we have another capacitor of 00:06:22
six milli farads so we would need to do this again but instead of two and four this value 00:06:29
would be 1.33 and instead of four six yeah so just to finish one the last one and a mixed 00:06:39
circuit no I don't want to see so something like that something like that okay it's a mixed circuit 00:06:50
here we have two capacitors connected serially and together parallel okay so how do we solve this 00:07:13
so path by path so first of all these two these two are connected serially sorry I forgot to type 00:07:30
the value so maybe four milli farads four milli farads 10 9 9 8 8 8 milli farads and here for 00:07:40
okay so first of all this we can call this one two and three okay so consider one two is four 00:08:01
multiplied by 8 here 4 plus 8 so this is 32 over 12 we can divide this by 4 for 8 over 3 and it is 00:08:21
2.67 67 watt milli farads okay always the same unit so we can type here milli farads okay and 00:08:44
then this this condenser that is the same as this two it's connected parallel in parallel with the 00:09:00
third one okay so total resistance is as we said that is in parallel we just need to add both c1 2 00:09:13
plus c3 so if we are 2.67 and 4 milli farads we have 667 okay so just to finish and what I remember 00:09:26
from now what I want you to know for the we are going to have an exam I'm going to tell you it in 00:09:52
the post okay what I want you to know and what I want you to know to the exam and the exam will 00:10:00
consist in a form in a form in Google okay and resistances for instance if I tell you we have a 00:10:12
resistance with this next bunch orange brown blah blah blah tell me the value of the resistance 00:10:29
symbols symbols of and diodes capacitors and resistances you know 00:10:36
and potentiometer I told you also and exercises with diodes which 00:10:50
which lamp lamps and this total total capacity more or less this is the and then I'm not going 00:11:11
you to to memorize anything because you are going to you can check all the information in your notes 00:11:39
it doesn't matter okay so that's all that's all okay see you stay at home see you ciao 00:11:50
Idioma/s:
es
Autor/es:
Iván PB
Subido por:
Ivan P.
Licencia:
Reconocimiento
Visualizaciones:
7
Fecha:
26 de julio de 2023 - 12:11
Visibilidad:
Clave
Centro:
IES JOSÉ SARAMAGO
Duración:
12′ 01″
Relación de aspecto:
1.78:1
Resolución:
1920x1080 píxeles
Tamaño:
18.86 MBytes

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