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3ºTEDI BLOCK4 SERIES CIRCUIT EXERCISE 1 - Contenido educativo
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This is the block 4, C-kits in series.
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In this exercise, you have to calculate several questions here.
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First, I recommend you to draw the C-kit.
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Three resistors in series and the cell.
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First questions.
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The first question is to calculate the equivalent resistance.
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The equivalent resistance in the C-kitting series is the addition of all the resistors that you have in the C-kit.
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So, you have this result.
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The total current always is the voltage of the cell divided by the equivalent resistance.
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Make the calculation with the calculator.
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In the following question, they are asking you the current in every of the resistors.
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here what you have to know is a property of the circuits in series the intensity or current is
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always the same so it's equal to the total intensity because there is only one path for
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the electron for the electrons to go through the circuit but in question d they are asking you to
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calculate voltage in every of the resistors then apply the ohm's law in each of the resistors
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because you know the intensity and you know the resistance and then calculate in each resistor
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that's why i call them voltage sub one means for the voltage in the resistor number one
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intensity by resistance in all of them use the calculator again so you always have the same
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intensity and this is the resistance of this of each of them check that the addition of the three
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voltages is the voltage of the cell. You can use a calculator to check this.
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In the last question, they are asking you to calculate the power, the power generated by the
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cell and the power dissipated by each of the resistors. The power is the voltage by the
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intensity. So the power generated is the voltage of the cell by the total intensity of the CKIT.
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then the power generated is this amount the power dissipated is dissipated in each of the
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resistors that they are the load devices the devices that are creating our work
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in each of them you can calculate the voltage by the intensity because you know it from the
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previous questions so you calculate the power in the first resistance the power in the second and
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the power in the third multiplying the voltages that you obtain and the intensity remember that
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was the same the unit of the power is the butt and it's really little the these figures are
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really little because the voltage of the cell was only three volts is really small and the
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intensity was only 0.1 amperes one thing that you have to check is that the addition of the three
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power dissipated in each of the resistors the addition of these three
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it's exactly the same as the power that you have in the cell.
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That's why we can say that the power generated is equal to the power dissipated in the circuit.
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- Autor/es:
- BEATRIZ TORREJON
- Subido por:
- Beatriz T.
- Licencia:
- Reconocimiento - No comercial - Sin obra derivada
- Visualizaciones:
- 41
- Fecha:
- 28 de abril de 2024 - 13:32
- Visibilidad:
- Público
- Centro:
- IES CERVANTES
- Duración:
- 03′ 22″
- Relación de aspecto:
- 1.78:1
- Resolución:
- 1280x720 píxeles
- Tamaño:
- 223.02 MBytes
