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Divisor of intensities - Contenido educativo

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Subido el 10 de abril de 2023 por Beatriz T.

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In a series parallel circuit, you have to use the specific characteristics of series or parallel 00:00:00
in each branch of the circuit. In the circuit, you can see here there is a resistor in series 00:00:06
with two that are in parallel. Firstly, calculate the equivalent resistance. 00:00:12
You calculate the resistors that are in parallel and then add the one that is in series. 00:00:19
The second question is the total current, remember is always the voltage of the cell 00:00:24
divided by the equivalent resistance. In this exercise they are asking for the currents trough 00:00:30
each resistor, the resistor 1 is in series with the cell, so the intensity is the same that in 00:00:37
the circuit. But this intensity is divide between the two resistors in parallel. The voltage here 00:00:43
is not the voltage of the cell. You can calculate it because the voltage is the difference between 00:00:51
the voltage of the cell and the voltage of the resistor 1. Other way to calculate the intensities 00:00:57
is through the divisor of intensities. It is a proportion between the equivalent resistance in 00:01:03
the parallel branch and the resistance of each of the parallel resistors. You decide with way is easier. 00:01:10
Autor/es:
BEATRIZ TORREJÓN TÉVAR
Subido por:
Beatriz T.
Licencia:
Reconocimiento - No comercial
Visualizaciones:
23
Fecha:
10 de abril de 2023 - 21:24
Visibilidad:
Público
Centro:
IES CERVANTES
Duración:
01′ 21″
Relación de aspecto:
1.78:1
Resolución:
1280x720 píxeles
Tamaño:
8.70 MBytes

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