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Resolución de Circuitos Simples - Contenido educativo

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Subido el 11 de enero de 2024 por Jose G.

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you 00:00:00
hello in this video we are going to solve simple circuit problems, simple circuits 00:00:30
are those that only have a single receiver and in this case they are going to be 00:00:37
electrical resistors so we are going to solve the first problem the statement says given the circuit 00:00:42
of the figure knowing the value of the vp battery are 10 volts the current intensity and are 2 00:00:49
amps calculate the value of the resistance r of the circuit well what we are going to do now 00:00:56
the first thing is to put the law of r is going to be equal to the voltage of the battery divided by the 00:01:03
current intensity and we are going to square it 00:01:14
now the next thing is going to be to replace the values ​​we have r no 00:01:25
so we leave it as it is we have vp if according to the statement they are 10 volts 00:01:32
we have the current intensity if they are 2 amps with which we are going to put it down here r is going to 00:01:39
be equal to 10 by 2 5 and as the semidenomial resistors we put their corresponding humidity 00:01:50
now what we are going to do is square the solution this is always done both in mathematics 00:01:59
as in technology and next year in physics and chemistry it is very good now we are going to see another problem 00:02:06
here we already have the second problem in this case or as you see it is the same scheme and the 00:02:24
statement given the circuit of the figure calculate the value of the intensity and if the resistance r 00:02:31
is 5 ohms and the vp battery is worth 60 volts because nothing we do the same we are going to put the 00:02:38
law of today again we put r is going to be equal to the voltage of the vp battery divided by the current 00:02:45
and we will square it again to distinguish it from what we are going to do next 00:02:54
we put a comma so that there are no errors and we replace the values ​​we give r if 5 or less because we put it 00:03:02
we have the value of the vp battery if 60 volts we are going to make the line a little more it gives us 00:03:16
the current intensity it is not just what it asks us very well because we clear it is there that it is 00:03:24
dividing it has to pass here multiplying and these 5 miles that are multiplying pass 00:03:32
dividing because this would be left to us in this way and it will be equal to 60 volts divided by 00:03:37
5 or less we go down here and it will be equal to 65 they will be 12 amps 00:03:48
this would be the solution and as I said in the previous problem we are going to square the solution 00:04:00
and so it would be solved well now we are going to do a third problem more we are going to look for it 00:04:07
here we have the third problem as you can see we continue to maintain the same scheme we are going to 00:04:27
see what the statement says given the circuit of the figure calculate the value of the vp battery if 00:04:34
the resistance r is of isomers and the intensity and is equal to 4 amps that is to say they are not 00:04:41
asking for the value of the battery because nothing we put the law of or and we start as 00:04:48
always r is going to be equal to vp divided by the current intensity and as the previous time 00:04:54
we are going to square it well we substitute we know r if it tells us that they are 6 or mine because we are going to place them 00:05:04
with or vp it is not just what they ask me I know the current intensity if how much is 4 00:05:18
4 amps because we have to clear this as we clear it because in this case 4 amps that is 00:05:27
here dividing happens by multiplying with which I would have that vp is going to be equal to 6 or mine by 00:05:36
4 amps the product would be 6 by 4 24 and the units in which the voltage is measured would be in 00:05:45
this case volts the small water then this would be like this vp will be equal to 24 volts and 00:05:58
like the previous programs we will continue to square it and with this we would already have the three 00:06:08
types of problems that we can find in the simple circuits formed by a single 00:06:19
receptor that in this case is an electrical resistance I hope it will serve you 00:06:25
Subido por:
Jose G.
Licencia:
Todos los derechos reservados
Visualizaciones:
78
Fecha:
11 de enero de 2024 - 17:30
Visibilidad:
Público
Centro:
IES JIMENA MENÉNDEZ PIDAL
Duración:
06′ 31″
Relación de aspecto:
16:9 Es el estándar usado por la televisión de alta definición y en varias pantallas, es ancho y normalmente se le suele llamar panorámico o widescreen, aunque todas las relaciones (a excepción de la 1:1) son widescreen. El ángulo de la diagonal es de 29,36°.
Resolución:
1088x614 píxeles
Tamaño:
126.11 MBytes

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