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2ESO_ELECTRICITY_PARALLEL CIRCUITS - Contenido educativo

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Subido el 27 de marzo de 2023 por Beatriz T.

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Parallel Cirque. In these circuits, the load devices are connected on different branches 00:00:00
of the wire. There are several possible paths for the electric current to flow through. 00:00:05
The electric current is split across all the possible paths and more current will circulate 00:00:11
through the branch that offers the least resistance. The current intensity that flows 00:00:15
through each load device is different. Even if one of the load devices stops working, 00:00:20
the rest continue to work because the electric current takes another path, 00:00:25
the circuit is closed by another path. The energy supplied by the cell reaches each branch of the 00:00:30
circuit directly. Therefore, all the lamps shine with the same brightness as a single lamp located 00:00:35
on a single branch. However, the cell will run down sooner. To simplify things, we will solve 00:00:41
a circuit formed by three resistors connected in parallel to a cell. The equivalent resistance of 00:00:48
a circuit with parallel resistors is calculated using this formula. Since this circuit is 00:00:54
equivalent to the last one, the current flowing through the two circuits will be the same. 00:01:00
We apply Ohm's law to calculate the current flowing through the equivalent resistance. 00:01:05
Since the resistors are in parallel, the potential drop or voltage is the same in them all and it is 00:01:11
equal to the cell voltage. Vt equals V1 equals V2 equals V3. By contrast, the total intensity 00:01:17
through the circuit is divided across all the resistors. We can calculate this with Ohm's law. 00:01:25
The total intensity is divided through the resistors in parallel, so the addition of the 00:01:32
intensities should give the total intensity. The inverse of the equivalent resistance is equal to 00:01:38
the sum of the inverses of all resistances in the circuit. The current of the equivalent circuit is 00:01:44
equal to the sum of the currents flowing across each of the resistors. The total voltage delivered 00:01:50
by the power source is the same as the potential drops across each of the resistors. Example of a 00:01:56
parallel circuit. From the parallel circuit shown in the figure, calculate the current flowing 00:02:02
through each resistor and the potential drop across each one. First, we use the above formula 00:02:09
to calculate the equivalent resistance. You need to use the calculator. Remember that the formula 00:02:15
gives you the inverse of the equivalent resistance, so you need to calculate the inverse. 00:02:23
Again use the calculator. We use Ohm's law to calculate the total current. 00:02:29
The potential drop in each branch is equal to the voltage supplied by the cell. 00:02:35
To calculate the current flowing through each resistor, 00:02:42
we apply Ohm's law using the voltage values that we just calculated. 00:02:45
So divide the cell voltage between each of the values of the resistors. 00:02:50
We can check that we have done the exercise correctly by adding up the current of all the 00:02:55
resistors. The result should be equal to the total current. 00:03:00
you 00:03:05
Autor/es:
BEATRIZ TORREJÓN TÉVAR
Subido por:
Beatriz T.
Licencia:
Reconocimiento - No comercial
Visualizaciones:
12
Fecha:
27 de marzo de 2023 - 12:01
Visibilidad:
Público
Centro:
IES CERVANTES
Duración:
03′ 06″
Relación de aspecto:
1.78:1
Resolución:
1280x720 píxeles
Tamaño:
37.22 MBytes

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